View source for Chapter 29 Problem 73

==Problem==
[[File:Chapter29Problem73q.png|300px|center|Rotating metal rod]]
A thin metal rod of length <math>l</math> rotates with angular velocity <math>\omega</math> about an axis through one end. The rotation axis is perpendicular to the rod and is parallel to a uniform magnetic field <math>\vec{B}</math> . Determine the emf developed between the ends of the rod

==Solution==
[[File:Chapter29Problem73s.png|300px|center|Rotation and flux]]
<math>d\mathcal{E}=Bvdr=B\omega r dr </math>

<math>\mathcal{E}=\int d\mathcal{E}=\int_0^{l}B\omega r dr=\frac{1}{2}B\omega l^2</math>