Difference between revisions of "105-2019201 Practice"

From 105/106 Lecture Notes by OBM
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===Question 1===
 
===Question 1===
 
Delta-v (literally "change in velocity"), symbolised as ∆v and pronounced delta-vee, as used in spacecraft flight dynamics, is a measure of the impulse per unit of spacecraft mass that is needed to perform a maneuver such as launch from, or landing on a planet or moon, or in-space orbital maneuver. It is a scalar that has the units of speed. As used in this context, it is not the same as the physical change in velocity of the vehicle.
 
Delta-v (literally "change in velocity"), symbolised as ∆v and pronounced delta-vee, as used in spacecraft flight dynamics, is a measure of the impulse per unit of spacecraft mass that is needed to perform a maneuver such as launch from, or landing on a planet or moon, or in-space orbital maneuver. It is a scalar that has the units of speed. As used in this context, it is not the same as the physical change in velocity of the vehicle.
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When rocket thrust is applied in short bursts the other sources of acceleration may be negligible, and ∆v becomes
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<math>\Delta V = \int_{t_0}^{t_1} \left|\vec{a}\right| dt</math>
  
 
As a simple example, take a conventional rocket which achieves thrust by burning fuel. Delta-v is the change in velocity that can be achieved by burning that rocket's entire fuel load.  
 
As a simple example, take a conventional rocket which achieves thrust by burning fuel. Delta-v is the change in velocity that can be achieved by burning that rocket's entire fuel load.  
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===(a)===
  
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Is it possible to calculate delta-v requirements of an orbital maneuver from conservation of energy by considering only the total energy of the vehicle in the initial and final orbits?
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===(b)===
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Orbit maneuvers are made by firing a thruster to produce a reaction force acting on the spacecraft. The size of this force will be
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<math>F_T=v_\text{exh}\rho</math>
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where <math>v_\text{exh}</math> is the velocity of the exhaust gas in rocket frame and <math>\rho=\frac{dm}{dt}</math> is the propellant flow rate to the combustion chamber.
  
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Assuming <math>v_\text{exh}</math> to be a constant not depending on the amount of fuel left prove the ∆v is given by  Tsiolkovsky rocket equation.
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<math>\Delta v = v_\text{exh}\ln\left(\frac{m_0}{m_1}\right)</math>
  
It is not possible to determine delta-v requirements from conservation of energy by considering only the total energy of the vehicle in the initial and final orbits since energy is carried away in the exhaust. For example, most spacecraft are launched in an orbit with inclination fairly near to the latitude at the launch site, to take advantage of the Earth's rotational surface speed. If it is necessary, for mission-based reasons, to put the spacecraft in an orbit of different inclination, a substantial delta-v is required, though the specific kinetic and potential energies in the final orbit and the initial orbit are equal.
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where <math>m_0</math> is the initial mass of the spacecraft (before the thrust), and <math>m_1</math> is the final mass of the spacecraft (after the thrust).  
  
  
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When rocket thrust is applied in short bursts the other sources of acceleration may be negligible, and the magnitude of the velocity change of one burst may be simply approximated by the delta-v. The total delta-v to be applied can then simply be found by addition of each of the delta-v's needed at the discrete burns, even though between bursts the magnitude and direction of the velocity changes due to gravity, e.g. in an elliptic orbit.
 
  
  
 
[[105-2019201 Solutions|solutions]]
 
[[105-2019201 Solutions|solutions]]

Revision as of 19:17, 22 December 2019


Question 1

Delta-v (literally "change in velocity"), symbolised as ∆v and pronounced delta-vee, as used in spacecraft flight dynamics, is a measure of the impulse per unit of spacecraft mass that is needed to perform a maneuver such as launch from, or landing on a planet or moon, or in-space orbital maneuver. It is a scalar that has the units of speed. As used in this context, it is not the same as the physical change in velocity of the vehicle.

When rocket thrust is applied in short bursts the other sources of acceleration may be negligible, and ∆v becomes

As a simple example, take a conventional rocket which achieves thrust by burning fuel. Delta-v is the change in velocity that can be achieved by burning that rocket's entire fuel load.

(a)

Is it possible to calculate delta-v requirements of an orbital maneuver from conservation of energy by considering only the total energy of the vehicle in the initial and final orbits?

(b)

Orbit maneuvers are made by firing a thruster to produce a reaction force acting on the spacecraft. The size of this force will be

where is the velocity of the exhaust gas in rocket frame and is the propellant flow rate to the combustion chamber.

Assuming to be a constant not depending on the amount of fuel left prove the ∆v is given by Tsiolkovsky rocket equation.

where is the initial mass of the spacecraft (before the thrust), and is the final mass of the spacecraft (after the thrust).












solutions